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MOSFETs like the ones in the MIC’s output stage can handle large current pulses for a short time by simply absorbing the heat generated by the pulse in their thermal mass.

IRLML 2803

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Sign fatasheet or log in Sign up using Google. On page 4, bottom right, there’s a graph showing the maximum safe operating area SOA of the device.


Sign up using Email and Password. The current might be internally limited. Mahendra Gunawardena 1, 9 It won’t be able to deliver 1A or more continuously, however – it can only do that for short pulses. Sign up using Facebook.

Without a gate resistor irlm,2803 only thing limiting the current is the gate driver’s output resistance, which is supposedly low, it would not be a good driver otherwise. As long as that doesn’t cause it to get hotter than its maximum junction temperature, no harm will be done.

Irlml datasheet pdf

The chip specifies the “typical” LO output dataseet as 1A, not an absolute maximum. Unimportant 1 6. Home Questions Tags Users Unanswered. So if you just darasheet its output to ground, it will die. It will survive a pulse of 7A at 20V just fine as long as it’s only 10 microseconds long.

The poly most modern processes use poly gates has some resistance; different Fabs have their own secret sauces. In fact, the datasheet for the MIC states: This current is limited by its internal output resistance since there doesn’t seem to be a limiting circuit according to the datasheet’s diagram of the output stage.


The FET can’t get rid of that heat but will absorb it in its thermal mass instead, heating up a little. I would place a 0 ohm resistor there for future experimentation.

Post as a guest Name. My thinking is this should lead to current peaks that easily exceed the driver’s 1A maximum peak current and damage the chip, but the evaluation board demonstrates that this is not the case, what am I missing? If the pulse is short enough, the FET will not heat up much and therefore survive just fine. At t 0 any capacitor will act like a short circuit. The Apps Engineer likely will not have access to any Fab details. That’s W dissipated in a SOT device. It’s not current that kills a FET, it’s overheating.

Owing to the fact that this gate driver features adaptive dead-time and thus monitors the gate of the MOSFET to determine when it has fully turned off, a gate resistor prevents proper sensing of the actual gate.